Question

In a triangle ABC, a = 5 cm, b =
3 cm and c = 2 cm , then Cos A is
equal to​

Answer 1

Answer :-

-1

Explanation:-

We have a = 5 cm

b = 3cm

c = 2cm

Therefore,

cos A = (b^2 + c^2 - a^2) / 2bc

cos A = {(3×3) + (2×2) - (5×5)} / 2×3×2

cos A = (9 + 4 - 25) / 12

cos A = (13 - 25) / 12

cos A = -12 / 12

cos A = -1

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Answer 2

Answer:

Given ,

a = 5cm

b = 3 cm

c = 2 cm

we know that

cos A = ( b^2 - c^2 + a^2 )/2bc

cos A = ( 3× 3 - 2 × 2 + 5 × 5)/ 2×3×2

cos a = ( 9 - 4 + 25 )/ 12

cos A = ( 13 - 25 )/ 12

cos A = - 12/ 12

cos A = - 1

Step-by-step explanation:

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