In a triangle ABC, A = 80° and B = 40°, then find angle C
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60 degree 180 - 120 is the answer
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The exterior angle is the sum of the interior opposite angles. Since AB=AC, ∠ABC=∠ACB.
Since the sum of angles in a triangle is 180
∘
, ∠BAC=100
∘
Hence, external angle at B = ∠ACB+∠BAC=100
∘
+40
∘
=140
∘
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