Question

In a triangle ABC, A-B=15 B - C =30
find the measure of each angle of the triangle​

Answer 1

Answer:

80,65,35

Step-by-step explanation:

in a triangle

A+B+C = 180   (as you may know)

give

A-B = 15  or A= 15+B

and, B-c = 30 or C= B-30

A+B+C=180

(15+B)+B+(B-30)= 180

3B - 15 = 180

3B = 195

B= 65

A= 80

C= 35

Answer 2

Answer:

∠A - ∠B = 15

So, ∠A = 15 + ∠B --->1

∠B - ∠C=30

So, ∠C = ∠B - 30 --->2

So, ∠A + ∠B + C=180° [Angle sum property of triangle]

15 + ∠B + ∠B + ∠B - 30 = 180

3∠B - 15 = 180

3∠B = 195

∠B = 65°

Substitute the value of B in 1 and 2

A = 15+B = 15 + 65 = 80°

C = B - 30 = 65 - 30 = 35°

So, ∠A= 80°,∠B = 65° , C=35°