In a triangle ABC,∆A= ∆C and ∆B = 80°find ∆A and ∆C
dhananjaysharma2:
50 degree
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Answered by
1
A=C=X
sum of angles of triangle=180°
A+B+C=180
X+80+X=180
2X+80=180
2X=180-80
2X=100
X=100/2
X=50
A=C=50
sum of angles of triangle=180°
A+B+C=180
X+80+X=180
2X+80=180
2X=180-80
2X=100
X=100/2
X=50
A=C=50
Answered by
0
Angle A = 50°
Angle C = 50°
HOPE THIS WILL HELP YOU
Angle C = 50°
HOPE THIS WILL HELP YOU
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