Question

In a triangle ABC a straight lune parallel to BC intersects AB and AC at point D and E respectively.If the area of the triangle ADE is one fifth of the area of triangle ABC and BC =10 cm then DE equals

Answer 1

$\sqrt[?]{?}$

[] \sqrt{?} [/tex]

Answer 2

Area of tringle ADE 1/5th of abc then BC=10cm &DE=5cm as DE=BC/2then. Area of tringle ADE/Area Of tringle ABC=DE squre/BC squre. 5*5/10*10=. 25/100==1/4Answer