Question

in a triangle abc, a=y, b=y-9, c=x, b-c=48. find the angles a, b and c​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Ina△ABC, (By angle sum property)

∠A+∠B+∠C=180

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∠C−∠B=9

⟹y−(3x−2)=9

∴y=7+3x

x+(3x−2)+y=180

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⟹4x−2+7+3x=180

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⟹x=25

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∴y=7+3×25=82

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∴∠A=x=25

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,B=3x−2=73

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∠C=y=82

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