In a triangle abc, ab=15 cm, bc=13 cm, and ac=14 cm. Find the area of the triangle and hence its altitude on ac
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Answer:
area of triangle = 1\2(bc×ac)
=1/2(13×14)
=1/2(128)
=64cm square
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Step-by-step explanation:
abc is a triangle.
ab+bc+ac =15+13+14=42
semiperimeter =42/2=21
area=√s(s-a)(s-b)(s-c)
=√21(21-15)(21-13)(21-14)
=√21×6×8×7
=√3×7×3×2×2×2×2×7
=84sqcm
altitude on ac=2×84/14=12cm.
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