Question

In a triangle ABC, AB = 15 cm, BC = 13 cm and AC = 14 cm. Find the area of ABC and hence it's altitude on AC ?

NO SPAM !​

Answer 1

In ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm.

By Heron's formula ,

S = ( A + B + C ) / 2

S = ( 15 + 13 + 14 ) / 2

S = 42 / 2

S = 21

Now, area of triangle

= √S (S–A) (S–B) (S–C)

= √21 (21–15) (21–13) (21–14)

= √21 (6) (8) (7)

= √7056

= 84 cm2

Again,area of triangle = 1/2×base×altitude=84 cm2

1/2×14×altitude = 84

7 × altitude=84

altitude = 84/7

Altitude = 12cm

Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm.

Step-by-step explanation:

ADVISE YOU CAN DOWNLOAD MY CBSE GUIDE FOR MORE PREFERENCE

Answer 2

Answer:

84; 12

Step-by-step explanation:

Please refer the attachment

and don't forget to Mark as brainliest and thank