In a triangle abc, Ab =15cm, Bc=13cm and Ac=14cm.
Find the area of triangle abc.
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Answer:
In ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm. Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm.
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Answer:
In ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm. Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm.
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