In a triangle ABC,AB=2a-1 ,AC=2√2a and BC=2a+1.Then angle BAC=?
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Answered by
14
here we see that
AB^2=4a^2-4a+1
BC^2=4a^2+4a+1
AC^2=8a^2
hence,
BC^2-AB^2=AC^2
so, BC^2=AB^2+AC^2
according to Pythagoras theorem
angles BAC is right angle , because their sides show Pythagoras theorem .
hence angle BAC=90 degree
AB^2=4a^2-4a+1
BC^2=4a^2+4a+1
AC^2=8a^2
hence,
BC^2-AB^2=AC^2
so, BC^2=AB^2+AC^2
according to Pythagoras theorem
angles BAC is right angle , because their sides show Pythagoras theorem .
hence angle BAC=90 degree
Answered by
4
Answer:I'm not understanding what abhi has written in tge second para
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