Question

in a triangle ABC ,ab=30 cm,BC=26cm and AC=28 cm .find the area of the triangle and it's altitude on AC
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Answer 1

using herons formula you can easily find this answer which equals to 336cm sq.

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Answer 2

Step-by-step explanation:

Given,

ab=30cm bc=26cm ac=28cm

S=a+b+c/2

= 30+26+28/2

=84/2

=42

Area=

$\sqrt{s(s - a)(s - b)(s - c) }$

=

$\sqrt{42(42 - 30)(42 - 26)(42 - 28)}$

=

$\sqrt{42 \times 12 \times 16 \times 14}$

=

$\sqrt{112896}$

$= 336cm^{2}$

Area of ∆ABC=1/2× base×height

$84cm ^{2} = 1 \div 2 \times 28cm \times h$

$h = (2 \times 84) \div 28cm$

$h = 168 \div 28$

$= 6$

therefore altitude on Ac= 6cm

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