Question

In a triangle ABC AB =6cm BC =7cm CA=10cm then the greatest angle

Answer 1

In any triangle angle opposite to the longer side is larger.

Here CA is the longest side and angle opposite to it is ∠B.

So ∠B is largest angle.

Then comes BC and angle opposite to it is ∠A

So angle A is second largest.

Then comes AB angle opposite to it is ∠C

So ∠C is smallest.

So the decreasing order of angles is

∠B>∠A>∠C

hope it hlps u

Answer 2

Concept: In any triangle, the angle opposite to the longer side is larger.

Given: $AB=6cm,\ BC=7cm,\ CA=10cm$

Find: greatest angle in the triangle

Solution:

If we make a triangle with given information, we find that angle opposite to the side of $AB$ is ∠$C$.

Similarly, angle opposite to the side $BC$ is ∠$A$ and angle opposite to the side $CA$ is ∠$B$.

We see that side $CA$ is longest which is $10cm$ long.

Hence angle opposite to the side $CA$ is the greatest.

So ∠B is the greatest angle here.

Therefore, we can say that ∠$A$ is smaller than ∠$B$ and ∠$C$ is smallest.

The decreasing order of the angles are

∠$B >$∠$A >$∠$C$

Therefore, The greatest angle is ∠$B$

#SPJ3