Question

IN A TRIANGLE "ABC" ,AB=AC=15cm, BC=18cm.

Find: a-cos angle ABC



b-sin angle ACB

Answer 1

Given,
AB = AC = 15 cm
BC = 18 cm
Now,
AB² = 15²
= 225
AC² = 225
BC² = 18²
= 324
Now,
AB² + BC² ≠ AC²
AB² + AC² ≠ BC²
AC² + BC² ≠ AB²
So, from inverse of Pythagoras thereom, we get that there is no 90° in the given triangle.
The given triangle is only an isosceles triangle.
So it is not possible to find any trignometric ratios.
Hope it may help you!!!!
Plz mark as brainlest!!!!