in a triangle ABC, AB=AC=15cm, BC=18cm find cos angle ABC.
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1
as we know cos =adjacent/hypotenuse
then cos is equal to 18/15
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9
Answer:
Answer:
In triangle ABC, AB = AC = 15 cm and BC = 18 cm then Cos∠ABC = 0.6
Step-by-step explanation:
AB = AC = 15 cm
BC = 18 cm
it is an isosceles triangle
if we draw AD ⊥ from A to line BC
it will bisect BC so BD = 18/2 = 9 cm
Δ ABD will be right angle triangle
with Base BD - 9 cm & Hypotenuse = AB = 15 cm
∠ABD = ∠ABC ( as D is a point on line BC)
Cos∠ABC = 9/15
=> Cos∠ABC = 3/5
=> Cos∠ABC = 0.6
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Step-by-step explanation:
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