Question

In a triangle ABC, AB=AC and line AO divides the base BC into equal parts. Prove that angle AOB = angle AO​

Answer 1

Answer:

<AOB = <AOC

Step-by-step explanation:

consider triangle ABO and ACO

AB=AC (Given)

BO=0C (Given)

AO=AO (Common)

Hence by SSS Property triangle ABO congruent to triangle ACO

Therefore, <AOB = <AOC (CPCT)

Hence proved

Answer 2

Answer is here ☝☝☝☝☝☝☝☝☝☝☝