In a triangle ABC, AB=AC and PR×CQ=AC². Prove that triangle BPA~triangle CQA
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Step-by-step explanation:
Given,
AB=AC
PB×CQ=AC2(As there is no mark as PR in the figure i considered it to be PB)
PB×CQ=AC×AC
PB×CQ=AB×AC
1/2 of (PB×CQ) = 1/2 of(AB×AC)
PB=AC
CQ=AC
IN TRIANGLE ABC:
AB=AC(given)
PB=AC(proved above)
CQ=AC(proved above)
therefore,
BPA~CQA(by SSS congruency)
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This is long answer question
Belonging to board examination
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