Question

In a triangle ABC, AB=AC. BA is produced to D and AE is drawn parallel to BC. Prove that AE bisects angle DAC.​

Answer 1

Answer:

• ∠DAE = ∠ABC  since these are corresponding angles in relation to the parallel lines AE and BC.
• ∠ABC = ∠ACB  since AB=AC, so triangle ABC is isosceles.
• ∠ACB = ∠CAE  since these are alternate angles in relation to the parallel ines AE and BC.

Therefore ∠DAE = ∠CAE.  That is, the line AE bisects the angle DAC.

Hope that helps.

Answer 2

Answer:

here give that ab=ac and exterior angle is equal to sum of interior opposite angles