In a triangle abc,ab=ac. Points d & e are on the sides bc and ac respectively such that ad=ae .If angle bad =10° then measure of angle bad
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AD = AE (this is an equation 1)
AB = AC (this is an equation 2)
Now we will subtract AD from both sides, we will get this:
AB – AD = AC – AD
AB – AD = AC - AE (Since, AD = AE)
BD = EC (this is an equation 3)
Now we will divide equation 1 by 2.
AD/DB = AE/EC
We will use Thales’ theorem here (DE‖BC )
∠DEC + ∠ECB = 1800
∠DEC + ∠CBD = 1800
So we know that quadrilateral BCED is cyclic.
Therefore, B,C,E and D are the concylic points.
If there is any confusion please leave a comment below.
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