In a triangle ABC ; AB, BC and CA are x, 3x+2 and x+4 units respectively where x in N .Find the lengths of its sides.
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Answer:
2 unit, 6 unit and 8 unit
Step-by-step explanation:
in a triangle the side of the longest side should be equal or be lesser than the sum of the length of other two sides
so let, the length of the longest side is equal to the sum of other sides ,
then ,
3x+2 = x + ( x + 4 ) [here ( 3x + 2 ) is the longest side ]
=> 3x +2 = 2x + 4
=> 3x - 2x = 4 - 2
=> x = 2
then the sides are , 2 unit , 6 unit and 8 unit
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