Question

In a triangle abc ab =bc angle b=50 find the value of angle a

Answer 1

Answer:

Since,

ab = bc

a = bc/b

a = c

Hence,

a+b+c = 180

a+50+c = 180

a+50+a = 180 [a = c]

2a+50 = 180

2a = 180-50

2a = 130

a = 130/2

a = 65

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Answer 2

Step-by-step explanation:

As,angle B =50°

And,AB=BC

THEREFORE, ANGLE A =ANGLE C

NOW,IN TRIANGLE ABC

A+B+C=180°

2A+50°=180°

A=130°/2

●THEREFORE ANGLE A = 65° ANS....

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