Question

in a triangle ABC AB greater than AC the bisector of Angle B and angle C meet at P prove that BP greater than CP​ and this question of class 9th

Answer 1

Answer:

Step-by-step explanation:

We know that if the bisectors of anglesand of ΔABC meet at a point O then .

Thus, in ΔABC

   ∠BPC=90°+1/2∠A          ……(1)

Also, using the theorem, “if the sides AB and AC of a ΔABC are produced, and the external bisectors of  and meet at O, then”.

Thus, ΔABC

∠BQC=90°−12∠A        ......(2)                

Adding (1) and (2), we get

∠BQC+∠BQC=90°+1/2∠A+90°-1/2∠A

∠BQC+∠BQC=180°

Answer 2

Answer:

proved

Step-by-step explanation:

in the picture above