Question

in a triangle ABC, AB is equal to AC if the bisector of Angle B and angle C meet AC and ab at points D and e respectively, show that; first triangle ABC is congruent to triangle ACB and second BD is equal to Ce ​

Answer 1

Answer:

Step-by-step explanation:

In quadrilateral ABCD we have

                 AC = AD

           and AB being the bisector of ∠A.

           Now, in ΔABC and ΔABD,

                 AC = AD

[Given]

                 AB = AB

[Common]

∠CAB = ∠DAB [∴ AB bisects ∠CAD]

           ∴ Using SAS criteria, we have

                 ΔABC ≌ ΔABD.

           ∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.

           ∴ BC = BD.

Answer 2

Answer:

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