Question

In a triangle ABC Abc =90 and Acb=30,, then find Ab/Ac​

Answer 1

Answer:

60°

Step-by-step explanation:

as,in ΔABC

∠ABC=90° & ∠ACB=30°

HENCE,

it is a right angledΔ

and AB/AC=sinθ(p/h)

also,

180°-(90°+30°)

=180°-120°

=60°

hence,

sinθ=60°

i.e;

$\frac{\sqrt{3} }{2}$

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Answer 2

Answer:

sin60°

=√3/2

Step-by-step explanation: