In a triangle ABC, AC = AB and the altitude AD bisects BC. Prove that ΔADC ≅ ΔADB.
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Answer:
Step-by-step explanation:
Given: AC = AB
AD bisects BC
To Prove: ΔADC ≅Δ ADB
Proof:
In ΔADC and ΔADB
1. AB = AC ------------- Given
2. BD = DC -------------( As AD bisect BC, given)
3. AD = DA -----------( Common side)
∴ ΔADC≅ ΔADB by SSS test
Hence proved
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