Question

In a triangle ABC, AC=CD and angle CAB- angle ABC=30 degrees. Then angle BAD is​

Answer 1

∠BAD = 15° if AC=CD and ∠CAB-∠ABC=30°

Step-by-step explanation:

AC=CD

=> in Δ ACD

∠CAD = ∠CDA  = x  ( let say)

then ∠CAD + ∠CDA + ∠C = 180°

=> ∠C = 180° - 2x

in Δ ABC

∠A + ∠B  + ∠C = 180°

=> ∠CAD + ∠BAD  + ∠B + 180° - 2x = 180°

=> x +  ∠BAD + ∠B  - 2x = 0

=> ∠BAD + ∠B = x

∠CAB- ∠ABC=30°

=> x + ∠BAD - ∠B = 30°

=> ∠BAD - ∠B = 30° - x

Adding both

2 ∠BAD = 30°

=> ∠BAD = 15°

Learn more

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Answer 2

Answer:

hi chirag026

Step-by-step explanation: