In a triangle ABC, AC>AB, Dis mid-point of BC and AE⊥BC. Prove that:
(a) AB2=AD2
- BC . DE +
BC2
(b) AC2=AD2 + BC . DE +
BC2
(c) AB2 + AC2 = 2AD2 +
BC2
please tell fast it is very urgent
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Answer:
ohh ! so sorry I think that the answer is B
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