Question

In a triangle ABC, AC>AB, Dis mid-point of BC and AE⊥BC. Prove that:

(a) AB2=AD2

- BC . DE +





BC2

(b) AC2=AD2 + BC . DE +





BC2

(c) AB2 + AC2 = 2AD2 +





BC2
​

Answer 1

Answer:

(a) ABgvsvsjjjbshhshxbb☺2=AD2

BC2