Math, asked by harshalabhinav397, 1 month ago

In a triangle ABC, AC is extended to D. If Angle BCD=6x+2,Angle BAC=3x+15,Angle ABC=2x-1, what will be the value of the triangle

Answers

Answered by nayanabaraiyaa
3

Answer:

× = 12

Step-by-step explanation:

ABC is a triangle and AC is extended to D. Thus <BCD is the exterior and the sum of <ABC and <BAC. Or

6x+2 = (3x+15) +(2x–1) = 3x+15+2x-1, or

6x-5x = 12, or

x = 12.

So <BAC = (3x+15) = 3x12+15 = 36+15 = 51 deg.

<ABC = (2x–1) = 2x12 - 1 = 24–1 = 23 deg

<ACB = 180–51–23 = 106 deg

<BCD = 74 deg.

x = 12.

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