In a triangle ABC, AC is extended to D. If Angle BCD=6x+2,Angle BAC=3x+15,Angle ABC=2x-1, what will be the value of the triangle
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Answer:
× = 12
Step-by-step explanation:
ABC is a triangle and AC is extended to D. Thus <BCD is the exterior and the sum of <ABC and <BAC. Or
6x+2 = (3x+15) +(2x–1) = 3x+15+2x-1, or
6x-5x = 12, or
x = 12.
So <BAC = (3x+15) = 3x12+15 = 36+15 = 51 deg.
<ABC = (2x–1) = 2x12 - 1 = 24–1 = 23 deg
<ACB = 180–51–23 = 106 deg
<BCD = 74 deg.
x = 12.
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