Math, asked by gogoidomborudhar, 13 days ago

In a triangle ABC, AD,BE,CF are the medians which intersect each other at G. To prove: GE =1/3 BE​

Answers

Answered by akashshinde9543
0

Answer:

BE is the median of ΔABC

so, ar(ΔBEC)=

2

1

ar(ΔABC) __(1)

Median of triangle divides into 2 triangles of equal area.

Also CF is median of ΔABC

⇒ar(ΔACF)=

2

1

ar(ΔABC) __(2)

from (1) and (2)

ar(ΔACF)=ar(ΔBEC)

ar(ΔGBC)+ar(ΔGEC)=ar(AFGE)+ar(GEC)

∴ar(ΔGBC)=ar(AFGE)

solution

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