Question

in a triangle ABC ad bisects angle BAC and AD is equal to DC if angle b is equal to 70 degree calculate angle ACD and angle AB d ​

Answer 1

Answer:

Given, in triangle ABC, AD bisects angle BAC and AD = DC.

and ∠BDA = 70

Now, ∠ADC = 110

and ∠DAC = ∠ACD    {since AD = DC}

Now, ∠ADC +∠DAC + ∠ACD = 180

=> 110 + ∠ACD + ∠ACD = 180

=> 110 + 2∠ACD = 180

=> 2∠ACD = 180 - 110

=> 2∠ACD = 70

=> ∠ACD = 70/2

=> ∠ACD = 35

So, ∠DAC = ∠ACD = 35

and ∠DAC = ∠DAB = 35

Again, ∠DAB +∠ABD + ∠BDA = 180

=> 35 + ∠ABD + 70 = 180

=> ∠ABD + 105 = 180

=> ∠ABD = 180 - 105

=> ∠ABD = 75

So, ∠ACD = 35 and ∠ABD = 75

Step-by-step explanation: