Question

In a triangle ABC, AD is a median and E is mid-point of median AD. A line through B
and E meets AC at point F.
Prove that : AC = 3

Hint:

Draw DG parallel to BF, which meets AC at point G.​

Answer 1

Step-by-step explanation:

let G be the midpoint of FC

In triangle BCF,D is the midpoint of BC and G is the midpoint of FC

hence,DG||BF= DG||EF

In triangle ADG,E is the midpoint of AD and EF||DG

SO,F is the midpoint of AG.

AF=FG=GC

=)AC=3AF