Question

In a triangle ABC AD is a median prove that AB +AC greater than 2AD

Answer 1

In triangles ABD and DGC, 
1. AD=DG [ by construction ]. 
2. BD=DC [ since AD is a median (given) ] 
3. included angle ADB= included angle CDG. 

Therefore, triangles ABD and DGC are congruent. [ by S.A.S. congruency. ] 

AB=CG, since they are corresponding sides of congruent triangles. 

In triangle ACG, 
AC+CG>AG. [ since sum of two sides of a triangle is greater than the third side. ] 
or, AC+AB>AD+DG. [ since AB=CG ( proved earlier ) ] 
or, AB+AC>AD+AD [ since AD=DG ( by construction )] 
or, AB+AC> 2AD. [ PROVED ] 

Answer 2

❤❤❤❤❤

$Heya \\</p><p>Plz\: see\: the\: attachment\\</p><p>Hope \: this \: helps \: u \\ </p><p>Follow \: me \\ </p><p>Plz \: mark \: my \: ans \: as \: brainliest$

❤❤❤❤❤