in a triangle ABC, AD is median and E is mid point of AC. DF is drawn parallel to BE such that it meets at F on AC. prove AC=1/4 AC
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How can u prove AC =1/4AC? Please correct the question
prove CF= 1/4 AC
E is midpoint of AC
Therefore AE=EC
In triangle BCE by midpoint theorem EF=F.C.
SIMILARLY by construction :G is midpoint of AB . GH parallel to BE.
Therefore AH=HE
Since AE=EC
AH+HE = EF+FC
AC=AH+HE+EF+F.C.
THEREFORE CF=1/4AC
HENCE PROVED
HOPE THIS IS HELPFUL.......
Therefore AE=EC
In triangle BCE by midpoint theorem EF=F.C.
SIMILARLY by construction :G is midpoint of AB . GH parallel to BE.
Therefore AH=HE
Since AE=EC
AH+HE = EF+FC
AC=AH+HE+EF+F.C.
THEREFORE CF=1/4AC
HENCE PROVED
HOPE THIS IS HELPFUL.......
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