in a triangle ABC AD is perpendicular bisector of BC show that triangle ABC is an isosceles triangle withAB=AC
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Step-by-step explanation:
in △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
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Answer:
By SAS criteria AB=AC is an isosceles triangle
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