Question

in a triangle ABC,AD is the bisection of angle A then the ratio of AB and AC is​

Answer 1

Step-by-step explanation:

Given AB = c =3, AC = b = 6 and BC = a = 3√3,

cos(A) = (b^2 + c^2 - a^2)/(2bc) = (36 + 9 - 27)/(36) = 1/2. ==> A = 60º

cos(B) = (c^2 + a^2 - b^2)/(2ca) = (9 + 27 - 36)/(18√3) = 0 ==> B = 90º

∆ABD is a right angled triangle, with B = 90º

|AB|/|AD| = 3/|AD| = cos(30º) = √3/2. ==> |AD| = 2√3