Question

in a triangle ABC, AD is the bisector of angle A, meeting side BC at D,

if AC=4.2CM, DC=6CM and BC=10CM, find AB​

Answer 1

Answer:

5.85(approximately)

Step-by-step explanation:

a

/ |\

/ | \

/ | \

/ | \

b/____ |___ \c

d

ac=4.2,DC=6 bc=10

ad²+ dc²= ac² (Pythagoras)

ad²+36= 4.2²

ad²= 17.64-36

ad= 4.28

ad²+ bd²=ab² (bd=10-6 =4)

4.28²+4²= ab²

ab²=34.3

ab=5.85

Answer 2

Answer:

5.85 (approximately)

Step-by-step explanation:

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