Question

In a triangle ABC, AD is the bisector of angle A, meeting side BC at D. If AD=5.6cm, BC=6cm and BD=3.2cm, find AC.

Answer 1

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Answer 2

Answer:

AC=6.26cm

Step-by-step explanation:

We are given that In a triangle ABC, AD is the bisector of angle A, meeting side BC at D. If AD=5.6cm, BC=6cm and BD=3.2cm.

Since, DC=BC-BD

⇒DC=6-3.2

⇒DC=2.8cm

Now, from ΔADC, we have

$(AC)^{2}=(AD)^{2}+(DC)^{2}$

Substituting the values, we get

$(AC)^{2}=(5.6)^{2}+(2.8)^{2}$

$(AC)^{2}=31.36+7.84$

$(AC)^{2}=39.2$

$AC=6.26cm$

Thus, the value of AC will be 6.26 cm.