In a triangle ABC, AD is the bisector of <A, meeting BC at D. If AD=5.6cm, BC=6cm and BD=3.2cm, find AC.
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given,
AD=5.6
BC=6
BD=3.2
angle bad=angle dac. AD bisect angle A
To find AC
Dc=BC-BD
DC=6-3.2
=2.8cm
angle D is of 90°
By paythgoras theorm
ac^2=ad^2+dc^2
= 5.6^2+2.8^2
=31.36+7.84
=39.2
squaring on both side
so
ac =6.2cm
AD=5.6
BC=6
BD=3.2
angle bad=angle dac. AD bisect angle A
To find AC
Dc=BC-BD
DC=6-3.2
=2.8cm
angle D is of 90°
By paythgoras theorm
ac^2=ad^2+dc^2
= 5.6^2+2.8^2
=31.36+7.84
=39.2
squaring on both side
so
ac =6.2cm
tigon:
why angle d is 90°?
ad bisect angle a
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