Question

in a Triangle ABC, AD perpendicular to BC then prove that AB2 + CD2 =AC2 + BD2
${ab }^{2} + {cd}^{2} = {ac}^{2} + {bd}^{2} is \: to \: prove$

Answer 1

in triangle ABC ,
AD perpendicular BC
proof : in triangle ,ABD
AD2=AB2-BD2 -(1)
in triangle ,ADC
AD2=AC2- CD2. -(2)
from (1) and (2) ,we get
AB2-BD2 =AC2-CD2
AB2+CD2= AC2+ BD2

proved

Answer 2

Answer:

Step-by-step explanation:

Understand and do it