In a triangle ABC an altitude drawn from A on side BC concides with the perpendicular bisector of BC .If AB = 5 cm ,then find the length of AC
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Steps of construction:
1. BC=5cm is drawn and is constructed downwards.
2. BX is drawn perpendicular to BY.
3. Q is drawn perpendicular bisector if BC intersecting BX at O and cutting BC at E.
4. Taking O as a centre and OB as radius, a circle is drawn.
Taking E as centre and radius equal to 3.5cm, arc is drawn to cut the circle at A.
5. AC and AB are joined.
6. AD is drawn perpendicular to BC from A to cut BC at D.
7. By measuring we find that AD=3cm.
solution
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