In a triangle ABC, angel a = x degree, angel b = 3x degree and angel c = y degree if 3y - 5x = 30, prove that the triangle is right angled show this by elimination method
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hence it become right angle triangle
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Heya!!Here is your answer friend ⤵⤵
Given angles of triangle are x , 3x and y respectively.
Using angle sum property of a triangle,
X+ 3x + y =180
-5 (4x + Y = 180.).......(1)
4 (-5X +3y= 30).....(2)
-20X-5Y = -900
-20X +12 y = 120
+. - -
-17 Y = -1020
Y= 1020/17
Y= 60 degrees
4x +60 = 180
4x = 120
X= 30.
Hence the other two angles are
30 degree and 3×30= 90 degrees.
➡it is clear that the triangle is a right angled triangle as one of its angle = 90.
Hope it helps you ✌✌
Given angles of triangle are x , 3x and y respectively.
Using angle sum property of a triangle,
X+ 3x + y =180
-5 (4x + Y = 180.).......(1)
4 (-5X +3y= 30).....(2)
-20X-5Y = -900
-20X +12 y = 120
+. - -
-17 Y = -1020
Y= 1020/17
Y= 60 degrees
4x +60 = 180
4x = 120
X= 30.
Hence the other two angles are
30 degree and 3×30= 90 degrees.
➡it is clear that the triangle is a right angled triangle as one of its angle = 90.
Hope it helps you ✌✌
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