Math, asked by aloksinghr100, 3 months ago

in a triangle ABC, angel B=90°, AC=16cm,BC=8cm and B is perpendicular to AD, area of triangle ADB​

Answers

Answered by chaithanyakumarb3
0

Step-by-step explanation:

\abc=\b+\ac+\bc=180°

90°+16+8= 180°

114=180°

1.578947368421

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