in a triangle ABC angle =90 and a= 8 by 11 sshow that secsq. A-tan A-1
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:-. In ∆ABC, ∠B = 90° . sin A = 8/11 . To Show :-. Sec²A - tan^2A = 1; Cot^A - Cosec^A + 1 = 0. Solution :-. we know that
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