Question

In a triangle abc angle a=1/2 angle b =1/6 angle c find angle a

Answer 1

Answer:

a = 20

b = 40

c = 120

Step-by-step explanation:

a = b/2

=> b = 2a

a = c/6

=> c = 6a

in a triangle,

sum of 3 angles = 180

=> a+b+c = 180

=> a+2a+6a = 180

=> 9a = 180

=> a = 180/9 = 20

=> b = 2a = 2×20 = 40

=> c = 6a = 6×20 = 120

Answer 2

The value of angle a is 113.68 degrees.

Step-by-step explanation:

According to the given information, we are given a triangle abc. Now, it is given that, angle a is equal to half of angle b. Also, it is given that, angle b is one-sixth of angle c. We need to find the value of angle a.

Now, let the value of angle a be x. Then, according to the given information, angle b will be half of angle a. Then, we have,

Angle b is equal to $\frac{x}{2}$.

Also, according to the given information, it is given that, angle c will be one sixth of angle b. Then, we have,

Angle c is equal to $\frac{1}{6} (\frac{x}{2} )$ or $\frac{x}{12}$.

Now, we know that, the sum of the angles of a triangle is equal to 180 degrees.

That is, the sum of the angles of the triangle abc is 180 degrees.

That is, the sum of angles a, b and c of the triangle abc is 180 degrees.

Thus, we get,

x +  $\frac{x}{2}$ + $\frac{x}{12}$ = 180

Or, $\frac{12x+6x+x}{12} =180$

Or, $\frac{19x}{12} =180$

Or, x = 113.68 degrees.

Thus, the value of angle a is 113.68 degrees.

Learn more here

https://brainly.in/question/19737895

Learn more

https://brainly.in/question/24155156