in a triangle abc angle A = 100 degree AB = AC find Angle B and angle C
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Given
ABC is a isosceles triangle (two side are equal)
Angle BAC = 100°
let angle ABC be X
so angle ACB = X (since two side is equal so it's opposite angle of side is equal )
Sum of all angle of a triangle = 180°
X + X + 100° = 180°
2x = 80°
X = 40°
so angle B and C is 40°
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