In a triangle ABC angle A =120°. AD is perpendicular on BC . Also AB+ BD = CD, then find angle C.1. 30°2. 20°3. 15°4. 25°
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Answer:
The correct answer is (1) 30°.
Step-by-step explanation:
[Figure has been provided below]
Angle A is given as 120°
When a perpendicular is drawn on BC, it bisects the angle A in two equal halves( forming two angles each 60°)
So now considering the smaller triangle, ADC, we have angle DAC = 60° and angle ADC as 90°
So, angle ACD comes as 180-( 60°+90°) = 30° [ Sum of all the three angles of a triangle is 180°].
Therefore, we get angle C as 30°.
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