In a triangle ABC, angle A/2= angle B/3=angle C/4. Find each angle.
Answers
Answered by
0
Answer:
Given triangle ABC
∠A=2∠B=3∠C
Let ∠A=x
then ∠B=
2
x
∠C=
3
x
we know that sum of angles in a triangle = 160°
∠A+∠B+∠C=180°
x+
2
x
+
3
x
=180°
6
6x+3x+2x
=180°
11x=180×6
∠A=x=(98
11
2
)°
∠B=
2
x
=(49
11
1
)°
∠C=
3
x
=(32
11
8
)°
angles are (98
11
2
)°,(49
11
1
)° and (32
11
8
)°
Answered by
0
Answer:
triangle abc angle a is 2x b is 3x c is 4 x
sum of all angles is equal to 180 degree
2x+3x+4x=180
9x=180
x=180/9
x= 2
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