in a triangle ABC, angle A=2 angle b and angle a =1/3 angle c , find the measures of all three angles
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masabishiraj53:
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Answered by
29
Answer:
Step-by-step explanation:
let the angle B be x then,
angle A = 2 angle B
2x
also,
angle A = 1/3 of angle C
3 angle A = angle C
angle C = 3 multiply 2x
6x
Now,
In triangle ABC
angle A + angle B + angle C = 180
2x + x + 6x = 180
9x = 180
x = 20
hence,
angle A = 2x = 2 multiply 20 = 40
angle B = x = 20
angle C = 6x = 6 multiply 20 = 120
Answered by
11
Answer:
The above picture is the answer. Hope you will understand..
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