Question

In a triangle ABC angle A =(2x+5)° angle B=(3x-15)° and angle C= (5x+50)°, find the measure of smallest angle.​

Answer 1

Answer:

2x+5+3x-15+5x+50=180°

10x+30=180°

x=180-30/10

x=150/10

x=15

angle A=2x+5=2(15)+5=35°

angle B=3x-15=3(15)-15=30°

angle C=5x+50=5(15)+50=125°

•°•angle C is smallest

Answer 2

Question :-

In a triangle ABC angle A =(2x+5)° angle B=(3x-15)° and angle C= (5x+50)°, find the measure of smallest angle.

Answer :-

Given :

• Angle A = 2x +5
• Angle B = 3x -15
• Angle C = 5x + 50

To find :

• measure of smallest angle

Solution :

We know that sum of three angles of a triangle is 180 °

So ,

2x+5+3x-15+5x+50 = 180

10x + 40 = 180

10x = 140

x = 14 °

Now lets Substitute the value of x in the given angles to find their actual value

• Angle A = 2x + 5 =(2×14) +5 = 33°
• Angle B = 3x-15 = (3×14)-15 = 27°
• Angle C = 5x + 50 = (5×14)+50 = 120°

So the smallest of these three angles is angle B