Question

in a triangle abc angle A = 60 degree angle b = 50 degree and the bisectors of Angle B and angle C meet at O find angle BOC

Answer 1

angle A + angle B + angle C = 180 degree
hence angle C = 70 degree
Now..in triangle OBC
half angle B + half angle C + angle BOC = 180 degree
25 + 35 + angle BOC = 180 degree
angle BOC = 180 - 60 degree
HENCE, angle BOC = 120 degree


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Answer 2

Answer:angle BOC= 120°

Step-by-step explanation:

Angle A= 60°

Angle B= 50°

Angle C= by angle sum property (ASP)

angle BAC+angle ABC+angle ACB=180°

60°+50°+angle ACB =180°

110°+angle ACB=180°

Angle ACB= 70°

Now, OB and OC are the bisectors of the angles.

So, angle OBC = 50°/2

                         =25°

Therefore,angle OCB =35°

By angle sum property,

angle OBC+angle OCB+angle BOC=180°

25°+35°+angle BOC=180°

60°+angle BOC=180°

angle BOC= 120°